1.

1323с 441Iil the qusdratic equation ax bx6 0 does not have two distinct real roots, then the least value of2a "b is14721

Answer»

doesn't have distinct real roots so b^2=4ac b^2=24a or 2a=b^2/12so 2a+b=b^2/12+bb^2+12b/12b^2+36+12b-36/12=(b+6)^2/12-3minimum value will be -3



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