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13. If the gravitational force had varied as r 2 insteadof r-2. the potential energy of a particle at adistance from centre of earth would beproportional to(1)r-1(2) r-5/2(3)r-3/2(4)r-2​

Answer»

Answer:

None of the given OPTION is correct. The correct answer is \rm r^3.

Explanation:

The Gravitational force \rm F_g and the potential ENERGY \rm U of a PARTICLE are related as

\rm F_g = -\dfrac{dU}{dr}\\\therefore U=-\int\limits^r_0F_g\ dr'.

The gravitational force on the particle at r distance from the surface of the EARTH is given as

\rm F_g = \dfrac{GMm}{r^2}.

  • G = Universal Gravtitational constant.
  • M = MASS of the Earth.
  • m = mass of the particle.

\rm r^2\rm r^{-2}If the gravitational force had varied as instead  of , then, \rm F_g = GMmr^2.

In that case,

\rm U=-\int\limits^r_0(GMmr'^2)\ dr'\\=-GMm\int\limits^r_0r'^2\ dr'\\=-GMm\left ( \dfrac{r'^3}{3}\right )\limits^r_0\\=-GMm\left ( \dfrac{r^3}{3}-0\right )\\=-GMm\left ( \dfrac{r^3}{3}\right ).\\\Rightarrow U\propto r^3.



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