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13. If a, B. y are zeroes of polynomial x3 + px2 + x + 2 such that a + B +1 = 0 then show that2p + q = -5. |
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Answer» X^3+px^2+qx+2=0A+B+1=0A+B=-1A+B+Y=-2-1×A=-2A=2A+B+Y=-pA+B=-p-2----------(1)AB+BY+YA=c/aAB+2B+2A=c/a-1+2 (A+B)=qA+B=q+1/2---------(2)Using (1)&(2)-p-2=q+1/2-2p-4=q+1-2p-q-5=0Hence,2p+q= -5 4p²+q²+25+4pq+10q+20p |
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