1.

13. Force between two charges placed at a distance r in vacuum is F .Now a dielectric slab of K =4 is inserted between them .its thickness is r/2.The new force between the charges

Answer» 13. Force between two charges placed at a distance r in vacuum is F .Now a dielectric slab of K =4 is inserted between them .its thickness is r/2.The new force between the charges


Discussion

No Comment Found

Related InterviewSolutions