13. Five years ago a man was seven times as old as his son. Five years

1.	13. Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.
Answer» ANSWER: AGE of the SON =x Age of the father=7x Present ages=x+5 and 7x+5 future age of the son=x+10 father=7x+10 7x+10=3(x+10) x=5 7x=35 x+5=5+5=10 son age =10 father age =7x+5=7*5+5=40

13. Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.

Answer»

ANSWER:

AGE of the SON =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40

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13. Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.​

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13. Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.