13 A tonalmumher hewanb)(o(0) – InterviewSolution

1.

13 A tonalmumher hewanb)(o(0)

Answer»

ong>Answer:

When

15

Al

is bombarded with α particle , a radioactive isotope of phosphorous

15

P

30

is FORMED with the EMISSION of neutron.

13

Al

27

+

He

4

→

15

P

30

+

0

n

1

→

14

Si

31

+

1

e

0

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