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13. A pair of dice is rolled. Find the probability of getting() doublets(i) sum is 6(iii) sum is at least 10(iv) sum is at most 5(v) sum is multiple of 5.SOLVE THIS PROBLEM I WILL MARK YOU AS BRAINILEST |
Answer» Answer:i)Probability of getting doublets = 6/36 = 1/6 ii) Probability of getting the SUM 6 = 5/36 iii) Probability of getting at least 10 = 11/36 iv) Probability of getting the sum is almost 5 = 4/36 = 1/9 v) Probability of getting the sum multiple of 5 = 9 Step-by-step explanation:13.i) doublets MEANS getting same digit in both the dices. 1 = 1 2 = 2 3 = 3 4 = 4 5 = 5 6 = 6 Probability of getting doublets = 6/36 = 1/6 ii) 2 + 4 = 6 4 + 2 = 6 5 + 1 = 6 1 + 5 = 6 3 + 3 = 6 Probability of getting the sum 6 = 5/36 iii) 9 + 1 = 10 9 + 2 = 11 9 + 3 = 12 5 + 5 = 10 5 + 6 = 11 6 + 6 = 12 8 + 2 = 10 8 + 3 = 11 8 + 4 = 12 6 + 4 = 10 6 + 5 = 11 Probability of getting at least 10 = 11/36 iv) 2 + 3 = 5 3 + 2 = 5 4 + 1 = 5 1 + 4 = 5 Probability of getting the sum is almost 5 = 4/36 = 1/9 v) 3 + 2 = 5 2 + 3 = 5 4 + 1 = 5 1 + 4 = 5 8 + 2 = 10 2 + 8 = 10 6 + 4 = 10 4 + 6 = 10 5 + 5 = 10 Probability of getting the sum multiple of 5 = 9 HOPE IT HELPS U!MARK AS BRAINLIEST! |
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