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13. A ball is dropped from certain height such that thedistance travelled in last second is equal to thedistance travelled in first three second. Find its height |
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Answer» Answer: Hello! This may help you for SURE! Formula USED: sn=u+g/2(2n−1) Answer:125m Explanation: The distance covered in first 3 second s=1/2gt^2 =1^2×10×3^2 =45 Ball TAKES 'n' seconds to fall to the GROUND. The distance covered in the NTH second is sn=u+g/2(2n−1) =10/2(2n−1) =10n−5 Therefore 45=10n−5 n=5=t Therefore h=12*gt^2 =12×10×25 =125m |
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