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13.8 g of K2CO3 was treated by a series of reagents so as to covert all of its carbon to K2Zn3[Fe(CN)6]2. Calculate the mass (in g) of the product formed? (Molecular mass of K2Zn3[Fe(CN)6]2 = 698 u)

Answer» 13.8 g of K2CO3 was treated by a series of reagents so as to covert all of its carbon to K2Zn3[Fe(CN)6]2. Calculate the mass (in g) of the product formed?
(Molecular mass of K2Zn3[Fe(CN)6]2 = 698 u)


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