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13-21Q.10. find the equation of line passing throughpassing through the points (4,3) & (3,-5).a = -3i+j-k and 5 =21+4j-2k find a.6 & interprete the result. |
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Answer» slope=y2-y1/x2-x1=-5-3/3-4=-8/-1=8henceequation of liney-y1/y2-y1=m(x-x1/x2-x1)+cy-3/-8=8*(x-4/3-4+c3+y/8=8(x-4/-1)+cy-3=64(x-4)+8c |
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