128 Thermodynamics 21. Enthalpy changes for two reactions are given bythe equation2Cr(s) + O2(g)+ Cr2O3(s), AH = -1130 kJC(s) + ,(g)+ CO(g),AH = -110 kg.The enthalpy change for the reactionCr20, + 3C 2Cr + 3CO will be(1) -1460 kJ(2) -800 kJ(3) +800 kJ(4) 1020 kJ

128 Thermodynamics 21. Enthalpy changes for two reactions are given

1.	128 Thermodynamics 21. Enthalpy changes for two reactions are given bythe equation2Cr(s) + O2(g)+ Cr2O3(s), AH = -1130 kJC(s) + ,(g)+ CO(g),AH = -110 kg.The enthalpy change for the reactionCr20, + 3C 2Cr + 3CO will be(1) -1460 kJ(2) -800 kJ(3) +800 kJ(4) 1020 kJ
Answer» I THINK so c)+800kjExplanation:_110×3=_330and _11 30 will become + because REACTION is REVERSE