127 2/7 sqcm of sheet is required to make a hemispherical bowl. Let us

1.	127 2/7 sqcm of sheet is required to make a hemispherical bowl. Let us write by calculating the length of diameter of the forepart of the bowl.ANSWER Fast .
Answer» $\huge\red{\boxed{\sf AnSwer}}$ GIVEN :- 127 2/7 SQCM of sheet is required to make a hemisphere bowl To Find : what is the length of diameter of the forepart of the bowl. Formula USED :- ${\pink{\boxed{\small{\bold{T.S.A\: of\: a\: hollow\: hemisphere =\: 2{\pi}{r}^{2}}}}}}$ where, T.S.A = Total Surface Area Solution :- Let the RADIUS be r cm According to the QUESTION by using the formula we get, $\sf 2{\pi}{r}^{2} =\: 127\dfrac{2}{7}$ $\sf 2{\pi}{r}^{2} =\: \dfrac{889 + 2}{7}$ $\sf 2 \times \dfrac{22}{7} \times {r}^{2} =\: \dfrac{891}{7}$ $\sf {r}^{2} =\: \dfrac{891}{7} \times \dfrac{7}{2 \times 22}$ $\sf {r}^{2} =\: \dfrac{891}{\cancel{7}} \times \dfrac{\cancel{7}}{44}$ $\sf {r}^{2} =\: \dfrac{\cancel{891}}{\cancel{44}}$ $\sf {r}^{2} =\: \dfrac{81}{4}$ $\sf r =\: \sqrt{\dfrac{81}{4}}$ $\sf\pink{\pink{r =\: \dfrac{9}{2}\: cm}}$ Now, we have to find the diameter of the forepart of the bowl, As we know that, $\boxed{\bold{\small{Diameter =\: 2r}}}$ Given : Radius (r) = 9/2 According to the question by using the formula we get $\sf Diameter =\: {\cancel{2}} \times \dfrac{9}{\cancel{2}}$ $\sf\bold{\red{Diameter =\: 9\: cm}}$ ${\underline{\boxed{\small{\bf{\therefore The\: length\: of\: diameter\: of\: the\: forepart\: of\: the\: bowl\: is\: 9\: cm\: .}}}}}$