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12 show that there is no value of n for which (2" × 5") ends in 5. |
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Answer» 2^n * 5^n = 10^n^2 Any number multipliedby 10 always ends in 0. (The basic test of divisibility rule to check if anumber is divisible by 10 is whether the final digit of the number is 0). Thus, for any value of n, n^2 multipliedby 10 will also end in 0. As a result, the value of 10n2 will neverend with 5. |
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