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12. Sehar bought two dresses at 25000 each. She thesold one of them at a loss of 10%. At what priceshould she sell the second dress to gain 20% in |
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Answer» Answer: 30,000 Step-by-step explanation: 1st DRESS cost price = 25000 loss % = ( loss / c.p ) x 100 10 = ( ( c.p - s.p ) / c.p ) x 100 10 = ( ( 25000 - s.p ) / 25000 ) x 100 10 = ( ( 25000 - s.p ) / 250 10 x 250 = 25000 - s.p 2500 = 25000 - s.p s.p = 25000 - 2500 s.p = 22500 2nd dress cost price = 25000 profit = 20 % profit % = ( profit / c.p ) x 100 20 = ( ( s.p - c.p ) / c.p ) ) x 100 20 = (( s.p - 25000 ) / 25000 ) x 100 20 = ( s.p - 25000 ) / 250 20 x 250 = s.p - 25000 5000 = s.p - 25000 5000 + 25000 = s.p s.p = 30,000 |
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