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() 12 cm,98area of a triangle whose sides are 34 cm, 20 cm and 42 cm. Hence, find thelensth of the altitude lcorresponding torthe shortest side.d sbsm ai alldmu nA os61125 mef this field is sold'at thethe |
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Answer» Semiperimeter (s) = (42 + 34 + 20 ) / 2So it is = 96 / 2 = 48 cm. Using herons formula = (√s )(√s-a )(√s-b) (√s-c)By substituting s and a , b , c i.e the given sides.We have√48 ×√6 ×√14 ×√28So √(4 × 6 × 2) ×√6 ×√(7 × 2) ×√(7 × 4)Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm²Hence area is 336 cm² Now height corresponding to longest side implies that base is 42 cm and area remains same So area of triangle is 1/ 2 b × h336 = 1/ 2 × 42 × HHENCE H = 16 cm So height is 16 cm . |
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