12. A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 m

1.	12. A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 mx 6 m is dug outside the fieldand the earth dug out from this well is evenly spread over the rectangular field. How much willthe earth level of the field rise?
Answer» $\large \bf \: QUESTION$ A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 mx 6 m is dug outside the field and the earth dug out from this well is evenly spread over the rectangular field. How much will the earth LEVEL of the field rise? $\large \bf \: SOLUTION$ $Volume \: of \: well = 14 m \times 8 \times 6m \: \\ 672 {m}^{3}$ Volume of field = Volume of well → Length,Breath, HEIGHT = 672 $height \: = \frac{672}{length \times <klux>BREATH</klux>}$ $= > \: \frac{672}{60 \times 70}$ $0.16 \: m=16 \: <klux>CM</klux> .$ Hence, the earth level of the field rise is 16 cm Verified☑

12. A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 mx 6 m is dug outside the fieldand the earth dug out from this well is evenly spread over the rectangular field. How much willthe earth level of the field rise?

Answer»

$\large \bf \: QUESTION$

A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 mx 6 m is dug outside the field and the earth dug out from this well is evenly spread over the rectangular field. How much will the earth LEVEL of the field rise?

$\large \bf \: SOLUTION$