113terms of the AP:9, 17,25,... must be taken to give a sum of 636frst – InterviewSolution

1.	113terms of the AP:9, 17,25,... must be taken to give a sum of 636frst term of an APis 5, the last term is45 nnd
Answer» a=9d=17-9=8S=(n/2)(2a+(n-1)d)636*2=n(18+(n-1)8)1272=n(8n+10)1272=8n^2+10n8n^2+10n-1272=0n=12

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