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(111) Water is filled in a right cylindrical tank with base radius 14 cm, such that waterTevel is 3 cm below the top. When an iron ball is dropped in the tank, 3003 cmº ofwater flows out. Find the radius of the ball. |
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Answer» Answer: Consider the provided information. Radius of water TANK is 14 cm and water level is 3 cm below the top. When iron ball is dropped it water 3003 cm³ of water flows out. Volume of empty tank = \pi r^2 H The volume of ball = Volume of empty tank + Volume of water came out The volume of ball = \pi r^2 h + Volume of water came out The volume of ball = \frac{22}{7}\times14^2\times3 + 3003 cm³ The volume of ball = 1848 cm³ + 3003 cm³ The volume of ball = 4851 cm³ The volume of sphere is: V=\frac{4}{3}\pi r^3 Substitute the respective values in the above formula. 4851 =\dfrac{4}{3}\TIMES\dfrac{22}{7}\times r^3 r^3= \dfrac{4851\times3\times7}{22\times4} r^3=1157.625 r=10.5 Hence, the radius of the ball is 10.5 cm³. #Learn more Radius of a sphere is 14 cm. find the surface AREA of the sphere? |
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