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111) AD-(/X-4) Cm, AE = (5x-2) cm. DB-(3x + 4) cm and EC = 3x cm.In the adjoining figure, ΔΑΗIf AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC5. In the adjoining figure, Agik is similar tois similar to AA |
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Answer» Two Triangles are said to be similar if their i)corresponding angles are equal and ii)corresponding sides are proportional.(the ratio between the lengths of corresponding sides are equal) GIVEN:AK = 10cm, BC = 3.5cm & HK = 7cm∆AHK ~ ∆ABC AK/AC = HK/BC [corresponding sides of similar triangles are proportional] 10/AC = 7/3.510/AC = 70/3510/AC = 10/510AC = 10 × 5AC = (10 × 5) /10 AC = 5 cm Hence, the value of AC is 5 cm. |
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