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11(v - 8) and (3-4) |
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Answer» ong>Answer: Mark me BRAINLEIST Follow me Thank my answers ❤❤❤Mark me BRAINLEIST Follow me TSolution: We know that, sec2θ – tan2θ = 1 (sec θ + tan θ) (sec θ – tan θ) = 1 (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given) ∴ sec θ – tan θ = 17Solution: We know that, sec2θ – tan2θ = 1 (sec θ + tan θ) (sec θ – tan θ) = 1 (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given) ∴ sec θ – tan θ = 17Solution: We know that, sec2θ – tan2θ = 1 (sec θ + tan θ) (sec θ – tan θ) = 1 (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given) ∴ sec θ – tan θ = 17Solution: We know that, sec2θ – tan2θ = 1 (sec θ + tan θ) (sec θ – tan θ) = 1 (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given) ∴ sec θ – tan θ = 17Solution: We know that, sec2θ – tan2θ = 1 (sec θ + tan θ) (sec θ – tan θ) = 1 (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given) ∴ sec θ – tan θ = 17hank my answers ❤❤❤Mark me BRAINLEIST Follow me Thank my answers ❤❤❤Stars exist in a range of colors: red, orange, yellow, green, WHITE and blue with red being the coolest and blue being the hottest. A star's color indicates it's temperature, COMPOSITION and RELATIVE distance from earth. Its luminosity indicates its size, the brighter it is, the larger it isSolution: We know that, sec2θ – tan2θ = 1 (sec θ + tan θ) (sec θ – tan θ) = 1 (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7; (Given) ∴ sec θ – tan θ = 17 Explanation: Mark me BRAINLEIST Follow me Thank my answers ❤❤❤Mark me BRAINLEIST Follow me Thank my answers ❤❤❤Mark me BRAINLEIST Follow me Thank my answers ❤❤❤Mark me BRAINLEIST Follow me Thank my answers ❤❤❤ |
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