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11. The value of the expressionsin? 22°+sinº 68 °+ sinº 63º+cos 63°sin 27°cos? 22° + cos2 68°is(A) 3(B) 2(C) 1(D) 0 |
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Answer» Answer: sin^2 22+sin^2 68/COS^2 22+cos^2 68+sin^2 63+sin^2 27 sin^2 22+ cos^2 22/sin^2 68+cos^2 68+sin^2 63+sin^227 =1/1+1 =2 so in this QUESTION you have two know sinA =cos (90-A) cosA=sin (90-A) sin^2 A+cos^2 A=1 Step-by-step EXPLANATION: I have FOLLOWED you |
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