11. The sum of the digits of a 2-digit number is 8. If the number obta

1.	11. The sum of the digits of a 2-digit number is 8. If the number obtained by interchanging the digitsis 36 more than the original number find the number.
Answer» Step-by-step explanation: let the no be 10x+y, then DIGITS of no are x,y x+y = 8 ---- A 10y+x-(10x+y)=36 => 9(y-x)=36 y-x = 4 ----B A+B = 2Y =12 =y=6 A-B =2x=4 =x=2 no. is 26

11. The sum of the digits of a 2-digit number is 8. If the number obtained by interchanging the digitsis 36 more than the original number find the number.

Answer»

Step-by-step explanation:

let the no be 10x+y, then DIGITS of no are x,y

x+y = 8 ---- A

10y+x-(10x+y)=36

=> 9(y-x)=36

y-x = 4 ----B

A+B

= 2Y =12

=y=6

A-B

=2x=4

=x=2

no. is 26

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11. The sum of the digits of a 2-digit number is 8. If the number obtained by interchanging the digitsis 36 more than the original number find the number.​

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11. The sum of the digits of a 2-digit number is 8. If the number obtained by interchanging the digitsis 36 more than the original number find the number.