11. The ratio of the measures of a side of a triangle is 2:3:5. If the

1.	11. The ratio of the measures of a side of a triangle is 2:3:5. If thesemiperimeter is 90cm then find the measure of the longest side of thetriangle.
Answer» Answer: 2x + 3x + 5x = 90 10x = 90 x = 90/10 x= 9 then the sides are = 2x = 29 = 18 = 3x = 39 = 27 = 5x = 59 = 45 Now semiperimeter = SUM of sides of triangle/2 = 18+27+45/2 =45 using herons FORMULA =√s(s-a)(s-b) (s-c) =√45(45-18)(45-27)(45-45) = √45(27)(18)(0) = 0 please* *mark* *brainliest* it *TOOK* me so *much* *time*

11. The ratio of the measures of a side of a triangle is 2:3:5. If thesemiperimeter is 90cm then find the measure of the longest side of thetriangle.

Answer»

Answer:

2x + 3x + 5x = 90

10x = 90

x = 90/10

x= 9

then the sides are = 2x = 2*9 = 18

= 3x = 3*9 = 27

= 5x = 5*9 = 45

Now semiperimeter =

SUM of sides of triangle/2

= 18+27+45/2

=45

using herons FORMULA

=√s(s-a)(s-b) (s-c)

=√45(45-18)(45-27)(45-45)

= √45(27)(18)(0)

= 0

please mark brainliest it TOOK me so much time

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11. The ratio of the measures of a side of a triangle is 2:3:5. If thesemiperimeter is 90cm then find the measure of the longest side of thetriangle.​

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11. The ratio of the measures of a side of a triangle is 2:3:5. If thesemiperimeter is 90cm then find the measure of the longest side of thetriangle.