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11 p r = 12 p r-1Find rPermutation |
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Answer» Sorry , last one was wrong , $$r=9 & 16$$ by solving eq. $$ r^2 -25r+144=0$$ $$\\frac{11!}{r(r-1)!}= \\frac{12×11!}{(r-1)!} =$$ $$\\frac{1}{r} =12$$ $$r=\\frac{1}{12}$$ r=9 r = 1/12 |
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