1.

""_(11)Na^(24) is radioacitive and it decays to

Answer»

`""_(9)F^(20)` and `alpha`-PARTICLES
`""_(13)AI^(24)` and positron
`""_(11)Na^(23)` and neutron
`""_(12)Mg^(24)` and `BETA`-particles.

Solution :`""_(11)^(24)Na` is `beta`- radioactive.
`""_(11)^(24)Na to ""_(12)^(24)Mg+ underset(beta-"particle")(""_(-1)^(0)e)`


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