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11.If x=√3+√2/√3-√2 and y=√3-√2/√3+√2,find the value x^2+y^2 |
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Answer» Step-by-step EXPLANATION: X = √3+√2/√3-√2 ×√3+√2/√3+√2 = (√3+√2)²/3+2. ( a²-b² = (a+b)(a-b)) = 3+2√6+2/1 x = 5+2√6
y = √3-√2/√3+√2×√3-√2/√3-√2 = 5-2√6 x²+y² = (5+2√6)²+(5-2√6)² = 25 + 24 + 10√6 + 25 + 24 -10√6 = 50+48 = 98...:) |
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