11. For what angle of incidence the lateral shift produced by parallel

1.	11. For what angle of incidence the lateral shift produced by parallel sided glass siab is minimum
Answer» for i = 90° lateral shift is maximum. Lateral shift for a slab of t thickness = t x sin(i - r)/cosr when i = 90 LS = t x sin(90 - r) / cos r = t x cos / cos r = t L.S becomes equal to thickness t.hence for I=0° it is minimum

11. For what angle of incidence the lateral shift produced by parallel sided glass siab is minimum

Answer»

for i = 90° lateral shift is maximum.

Lateral shift for a slab of t thickness = t x sin(i - r)/cosr

when i = 90

LS = t x sin(90 - r) / cos r = t x cos / cos r = t

L.S becomes equal to thickness t.hence for I=0° it is minimum