Saved Bookmarks
| 1. |
11. Find the area of a triangle in which a=10 cm, b = 18 cm c=14 cm |
|
Answer» Answer: Given sides are 18cm,10cm and 14cm Area of triangle = s(s−a)(s−b)(s−c)
⇒a=18cm,b=10cm and c=14cm ⇒s= 2 a+b+c
= 2 18+10+14
= 2 42
=21cm Area = 21(21−18)(21−10)(21−14)
= 21×3×11×7
=21 11
sqcm Hence, the answer is 21 11
sqcm. plz FOLLOW me |
|