11. Construct a quadrilateral ABCD in which AB = 5.6 cm, BC = 4 cm, ZA

1.	11. Construct a quadrilateral ABCD in which AB = 5.6 cm, BC = 4 cm, ZA = 50°, ZB = 105°and ZD = 80°.
Answer» Answer: Step-by-step explanation: ∠A + ∠B + ∠C + ∠D = 360° so 50° + 105° + ∠C + 80° = 360° ∠C = 125° Now we will construct the quadrilateral ABCD - First we will DRAW a line AB = 5.6 cm - Now we will draw ∠BAX = 50° and ∠ABY = 105° (you can use protector for this) - The RADIUS we will TAKE is 4CM and the center will be B for that you will draw and arc which will intersect the line BY at "C" - Now we will draw an angle of 125° at "C" and the angle ray line AX at "D" Attached is the quadrilateral.

11. Construct a quadrilateral ABCD in which AB = 5.6 cm, BC = 4 cm, ZA = 50°, ZB = 105°and ZD = 80°.

Answer»

Answer:

Step-by-step explanation:

∠A + ∠B + ∠C + ∠D = 360°

so 50° + 105° + ∠C + 80° = 360°

∠C = 125°

Now we will construct the quadrilateral ABCD

- First we will DRAW a line AB = 5.6 cm

- Now we will draw ∠BAX = 50° and ∠ABY = 105° (you can use protector for this)

- The RADIUS we will TAKE is 4CM and the center will be B for that you will draw and arc which will intersect the line BY at "C"

- Now we will draw an angle of 125° at "C" and the angle ray line AX at "D"

Attached is the quadrilateral.

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