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11. A normal human eye can see an object making an angle of1.8° at the eye. What is the approximate height (h) of objectwhich can be seen by an eye placed at a distance of I.4 m?1.8° |
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Answer» tan(1.8°) = h/1.40.0314262660 = h/1.4h = 0.0314262660 x 1.4h = 0.0439967724 m thanks |
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