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11.2 L of oxygen STP and 8 grams of calcium are allowed to react. What volume of which chemical 3 is left unreacted? |
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Answer» Solution :The balanced chemical EQUATION is `2Ca+O_(2)to 2CaO` 2 moles of Ca=1 moles of `O_(2)` (2 x 40) grams of Ca=22.4 L of `O_(2)` at STP 8 grams of Ca=2.24 L of `O_(2)` at STP The limiting REAGENT is calcium. Volume of `O_(2)` at STP required=2.24 L Volume of `O_(2)` left unreacted =11.2-2.24 =8.96 L at STP |
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