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10years ago a mans age was 6 times the age of his son . 12 years later , the age of his son . 12 years later , age of the son will be 27 years . what is the present age of the father |
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Answer» Hello SHANAYA... let the CHILD's age be = x 10 years ago man's age was 6 TIMES of son so 10 years before FATHER's age=6x now 6(x-10 ) 12byears later sons age =27 so x+12=27 equations are father's current age=6(x-10) sons age after 12 years x+12=27 x can be x=27-12 x=15 sons current age=15 father's age =6(x-10) 6 X (15-10) 6 X 5 30 current age of father = 30yrs percent = 30%
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