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10th term from the end of an A.P. is its 11th term from the beginning. Its value is 55. If its first term be 5, find the common difference, the number of terms and the last term. |
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Answer» 5+10d = 5+ (n -10)d ⇒ 10d = nd - 10d ⇒ 20d =nd n =20 5+10d = 55⇒ d = 5 tn = 5+19 x 5 =100 |
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