1.

10th std, In a G.P 1/4, 1/2, 1, -2 . . . ., find t10

Answer»

Step-by-step explanation:

in the GIVEN gp

a = ¼

r = ½/¼

=> r = 2

so,

T10 = a. r^9

= ¼ ×2^9

= 512/4

= 128.

hence the 10th term is 128.



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