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10th std, In a G.P 1/4, 1/2, 1, -2 . . . ., find t10 |
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Answer» Step-by-step explanation: in the GIVEN gp a = ¼ r = ½/¼ => r = 2 so, T10 = a. r^9 = ¼ ×2^9 = 512/4 = 128. hence the 10th term is 128. |
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