10ml of a gaseous hydrocarbon on combustion gives 40ml of CO_(2) and 50ml of H_(2)O vapour under the same conditions. The hydrocarbon is

10ml of a gaseous hydrocarbon on combustion gives 40ml of CO_(2) and 5

1.	10ml of a gaseous hydrocarbon on combustion gives 40ml of CO_(2) and 50ml of H_(2)O vapour under the same conditions. The hydrocarbon is
Answer» `C_(4)H_(6)` `C_(6)H_(10)` `C_(4)H_(8)` `C_(4)H_(10)` SOLUTION :`C_(x)H_(y)rarrxCO_(2)+(y)/(2)H_(2)O` `10rarr40rarr50` `impliesx=4impliesy=10`