10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded. Volume of gaseous product after reaction is?

10g of hydrogen and 64g of oxygen were filled in a steel vessel and ex

1.	10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded. Volume of gaseous product after reaction is?
Answer» Hii There!!! Balance equation is :- 2H₂ + O₂ -------> 2H₂O Moles in 10g of hydrogen = mass/molar mass = 10g / 2 = 5 moles 64g of OXYGEN No. of moles = given mass/molar mass So, moles = 64/32 = 2 moles The mole reaction for the equation above is H₂ : O₂ is 2 :1 THEREFORE 5 moles of H₂ will REQUIRE 2.5 moles of oxygen - this makes oxgen the limiting reagent. We therefore use the moles of oxygen to find those of H₂O: mole ratio O₂ : H₂O is 1 : 2 That means 2 moles of oxygen will PRODUCE 4 moles of H₂O Now , If 1 mole = 22.4 liters Then 4 moles = 22.4 × 4/1 = 89.6 liters The volume of H₂O produced is 89.6 liters. Hope it helps