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10forA and Bmultiplicationare to notices conformablethen sand (AB) isNu |
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Answer» If A and B are two matriceswhich can be multiplied,then rank(AB) <= min(rank(A),rank(B) ). I want to prove the following,IfA is an M by nmatrixandBis a squarematrixofrankn,then rank(AB) =rank(A).If A and B are two matriceswhich can be multiplied,then rank(AB) <= min(rank(A),rank(B) ). |
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