Saved Bookmarks
| 1. |
) 1014 3)613 4) 2104 4, g (a)-2 then32. IE(a)-2,/(a)-1,g(a)--f(x),f(a)-g(a)lim =x-a1) 1/53) -1/5 4) -5 |
|
Answer» if we put x=a numerator and denominator both will be 0. so 0/0 form using L'Hospital Rulelim (f'(x)f(a)+f(x)f'(a)-g'(a))/1 x->a =f'(a)f(a)+f(a)f'(a)-g'(a)=1*2+2*1-(-1)=2+2+1=4+1=5 |
|