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101. What volume of oxygen at 18°C and 750 torr, can be obtain from 110g of kclo3a) 32.6Lb) 42.7Lc) 3.26 Ld)4.27L |
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Answer» Acc. To me, Your ANSWER is a ---------------------------------------------- T=18°=291K 750torr=0.98atm 110/122.5=MOLE of kclo3 1mole kclo3--------------3 mole O2 110/122.5 mole------------3*110/122.5 mole O2 3*110/122.5 mole O2------------3/2*110/122.5 mole O PV=nRT 0.98atm*V=3/2*110/122.5*0.0821*291 V=approx 32.4L -------------------------------------------------- I hope you UNDERSTAND my answer I you think any MISTAKE then comment me |
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