100 g solution of urea in water has 10 g of of urea (molar mass = 60g

1.	100 g solution of urea in water has 10 g of of urea (molar mass = 60g mol) the molality of solution
Answer» ONG>Answer: 1.84 m Explanation: step 1 : Find MOLES of solute. The solute in this case is urea. Let us find moles of urea. MOLE = gram/molar mass Molar mass of urea is 60.1 g/mol We have 10 grams of urea. Let us plug in these values to find moles. Mol = 10g /60.1 g /mol = 0.166mol We have 0.166 mol urea. Step 2 : Find mass of solvent Water is solvent here . The mass of solution is given as 100 g. Mass of solution = mass of solute + mass of solvent 100 g = 10 g + mass of solvent mass of solvent = 100 g - 10 g = 90 g = 0.09 kg Step 3 : Use molality formula The molality of a solution is calculated USING following formula m = solute/solvent = 0 .166mol / 0.09kg Molarity =1.84m Answer : The molality of the solution is 1.84 m Mark me as brainliest. plzz

100 g solution of urea in water has 10 g of of urea (molar mass = 60g mol) the molality of solution

Answer» ONG>Answer:

1.84 m

Explanation:

step 1 : Find MOLES of solute.

The solute in this case is urea. Let us find moles of urea.

MOLE = gram/molar mass

Molar mass of urea is 60.1 g/mol

We have 10 grams of urea.

Let us plug in these values to find moles.

Mol = 10g /60.1 g /mol = 0.166mol

We have 0.166 mol urea.

Step 2 : Find mass of solvent

Water is solvent here .

The mass of solution is given as 100 g.

Mass of solution = mass of solute + mass of solvent

100 g = 10 g + mass of solvent

mass of solvent = 100 g - 10 g = 90 g = 0.09 kg

Step 3 : Use molality formula

The molality of a solution is calculated USING following formula

m = solute/solvent = 0 .166mol / 0.09kg

Molarity =1.84m

Answer : The molality of the solution is 1.84 m

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