100 g of mercuric oxide decompose to give 92.6 g of mercury and 7.4 g

1.	100 g of mercuric oxide decompose to give 92.6 g of mercury and 7.4 g of oxygen. Let us assume that 10 g of oxygen reacts completely with 125 g of mercury to give mercuric oxide. Do these values agree with the law of constant proportions?
Answer» Proportion of oxygen = 7.4 : 10 Proportion of mercury = 92.6 : 125 \(\Rightarrow \,\frac{7.4}{10}=\frac{92.6}{125}\Rightarrow0.74=0.74\) ∴ They follow law of constant proportions.

100 g of mercuric oxide decompose to give 92.6 g of mercury and 7.4 g of oxygen. Let us assume that 10 g of oxygen reacts completely with 125 g of mercury to give mercuric oxide. Do these values agree with the law of constant proportions?

Answer»

Proportion of oxygen = 7.4 : 10

Proportion of mercury = 92.6 : 125

\(\Rightarrow \,\frac{7.4}{10}=\frac{92.6}{125}\Rightarrow0.74=0.74\)

∴ They follow law of constant proportions.