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100 cells each of emf 5V and internal resistance `1 Omega` are to be arranged to produce maximum current in a `25 Omega` resistance. Each row contains equal number of cells. Find the number of rows. |
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Answer» Total number of cells is mn = 100. (i) Current will be maximum when `R =(nr)/(m) or 25 = (nxx1)/(m)` n =25m (ii) From Eqs. (i) and (ii) we get n = 50 and m =2. |
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