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100 cells each of emf 5V and internal resistance `1 Omega` are to be arranged to produce maximum current in a `25 Omega` resistance. Each row contains equal number of cells. Find the number of rows.A. 2B. 3C. 50D. 40 |
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Answer» Correct Answer - A Let n be the number of cells in a row and m be the number of rows. Now, maximum current is obtained for `r=R`. In mixed combination total resistance of the circuit is given by, `R=(nr)/(m) :.25(n)/(m) r :. (n)/(m)=25` `:.n=25m` ....(i) In mixed combination, we have, `nm=100` ...(ii) From equation (i) and (ii) we have, `mxx25m=100` `25m^(2)=100` `m^(2)=4:.m=2 ` and `n=50` |
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