1.

10 years ago garima's mother was 4 times older than her daughter.after 10 years,the mother will be twice older than the daughter.the present age of garima is

Answer»

Let the present AGE of garima's mother age is =x YEARS
and present age of her garima =y years
10 years ago
Garima's mother age is =(x-10)years
and Garima age = (y-10 )years
by the given 1 conditions
×-10 =4 (y-10)
×-10 =4y-40
x-4y =-40+10
x-4y =-30 --------1 equation
by SECOND conditions
10 years after
Garima's mother age = (x+10) years
and Garima age = (y+10)years
i.e. x+10=2 (y+10)
x+10 = 2y +20
x-2y = 20-10
x-2y = 10 ----------------2 equation
equation 1 -equation 2
-2y = -40
y = 20
put in equation 2
x - 2 (20) = 10
x -40 =10
x = 40+10
x=50
HENCE
present age of Garima's mother is =50 years
and Garima ia= 20 years


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