10% urea solution is there at 27 C. Find out osmotic pressure

1.	10% urea solution is there at 27 C. Find out osmotic pressure
Answer» Osmotic presuure=i∗C∗R∗T where, C=concentration of solute(in terms of Molarity) R= Gas constant=0.082L(atm)(mol)^−1K^−1 T=temperature (in Kelvin) i=Van’t-Hoff factor(=1 for non-electrolyte) 10%urea solution means10gurea is present in 100ml of solution. mole of urea=weight given/Molecular weight of urea =10g/60gmol^−1=1/6 Hence Concentration of urea (in terms of Molarity) = (moles of urea(n) /volume of solution )×1000×1000 ={(1/6)/100}∗1000 5/3 Hence Osmotic pressure=1×(5/3)×0.082×300atm =41atm

Answer»

Osmotic presuure=i∗C∗R∗T

where, C=concentration of solute(in terms of Molarity)

R= Gas constant=0.082L(atm)(mol)^−1K^−1

T=temperature (in Kelvin)

i=Van’t-Hoff factor(=1 for non-electrolyte)

10%urea solution means10gurea is present in 100ml of solution.

mole of urea=weight

given/Molecular weight of urea

=10g/60gmol^−1=1/6

Hence Concentration of urea

(in terms of Molarity)

= (moles of urea(n) /volume of solution )×1000×1000

={(1/6)/100}∗1000

5/3

Hence Osmotic pressure=1×(5/3)×0.082×300atm

=41atm

Discussion