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10:Theperimeterofa rectangle is 90 cm and its area is 486 cm. Find the dimensions of thetangle.11 Which term ofthe AD. 2 1 7 20

Answer»

Length=LBreadth=BPerimeter of rectangle=2(L+B)=90L+B=45Area of rectangle=L*B=486; B=486/LL+486/L=45Take LCML^2+486=45LL^2-45L+486=0L=(45+-((45)^2-4(486))^.5)/2L=27,18B=486/L=27,18So dimensions are 27cm and 18cm

I don't understand



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