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10 The vapour pressure of a pure liquid is 0.043 barat certain temperature. When a non-volatile solutesdissolved into it, the vapour pressure of the solution isfound to be 0.041 bar. What is the relative loweringvapour pressure . |
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Answer» Answer: GIVEN- P1⁰= 0.043 P1 = 0.041 To FIND- RELATIVE Lowering of vapour pressure Formula- ∆P/ P1⁰= P1⁰- P1 / P1⁰ Solution- ∆P/P1=P1⁰-P1 / P1⁰= 0.043-0.041/0.043 = 0.0465 |
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