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10) The average speed at T K and most probable speed at T2K of CO, gas is 9 x 104 cm/sec.The values of T, and T2 are1) 2143 K; 1694 K 2) 1726 K;2126 K3) 1684 K ; 2143 K 4) 1684 K ;3368Kplz solve it correctly |
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Answer» answer is (1)EXPLANATION:Average speed = $\sqrt{(\large\frac{8RT}{\PI m})}$Most probable speed = $\sqrt{(\large\frac{2RT}{m})}$Average speed at $T_1 K$ = MP speed at $T_2K for\; CO_2$$\sqrt{(\large\frac{8RT_1}{\pi m})} = \sqrt{(\large\frac{2RT_2}{m})}$$\large\frac{T_1}{T_2} = \large\frac{\pi}{4}$------(i)Also for $CO_2 u_{mp} = \sqrt{(\large\frac{2RT}{m})} = 9\times10^4$$=\sqrt{\large\frac{2\times8.314\times10^7\times T_2}{44})}= 9\times10^4$By eq (1) We GET$T_2 = 2143.37K$$T_1 = 1684.0K$Hence answer is (1)hope...it..helps....make..me..brainlist.. |
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