1.

10. Prove that the mid-point of the hypotenuse of a right002triangle is equidistant from its vertices.

Answer»

Let P be the mid point of the hypo. of the right triangle ABC, right angled at B.

Draw a line parallel to BC from P meeting AB at D.

Join PB.

in triangles,PAD and PBD,

angle PDA= angle PDB (90 each due toconv of mid point theorem)

PD=PD(common)

AD=DB( as D is mid point of AB)

so triangles PAD and PBD are congruent by SAS rule.

PA=PB(C.P.C.T.)

but

PA=PC(given as P is mid point )

So,

PA=PC=PB



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