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10. Prove that the mid-point of the hypotenuse of a right002triangle is equidistant from its vertices. |
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Answer» Let P be the mid point of the hypo. of the right triangle ABC, right angled at B. Draw a line parallel to BC from P meeting AB at D. Join PB. in triangles,PAD and PBD, angle PDA= angle PDB (90 each due toconv of mid point theorem) PD=PD(common) AD=DB( as D is mid point of AB) so triangles PAD and PBD are congruent by SAS rule. PA=PB(C.P.C.T.) but PA=PC(given as P is mid point ) So, PA=PC=PB |
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