1.

10^n-1111=sum of the digits are 879,find n?​

Answer»

=  > 10 {}^{n}  - 1111 = 879 \\  =  > 10 {}^{n}  = 879  + 1111 \\  =  > 10 {}^{n}  = 1990 \\  =  >



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